2x^(1/2)+x^(1/4)+6=0

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Solution for 2x^(1/2)+x^(1/4)+6=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

2*x^(1/2)+x^(1/4)+6 = 0

t_1 = x^(1/4)

2*t_1^2+1*t_1^1+6 = 0

2*t_1^2+t_1+6 = 0

DELTA = 1^2-(2*4*6)

DELTA = -47

DELTA < 0

x belongs to the empty set

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